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CONTENTS

Composite, Prime

Palindromic Sophie Germaine Primes (1 & 2)

Prime 30103

Fermat & Mersenne Numbers

Minimum Difference Prime Squares Prime Queen Problem

Ulam's Prime Spiral

Primes Adjacent to 6n

A Reversible Sequence

Prime 5882353

Primes Plus Even Number 8 Consecutive Primes

Prime Rectangles

A Prime Staircase

Prime 1129

Fermat Product Plus 2

Perfect Numbers from Primes

Primeval Primes

A Prime Circle

Prime # 57

Butterfly Primes

Composite, Prime

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NOTE: pattern alternates between composite and prime (until x=10). Too bad !

A. H. Beiler, Recreations in the Theory of Numbers p. 85

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Palindromic Sophie Germaine Primes (1)

                191 & 383

39493939493 & 78987878987

If P is greater than 2 and is a prime, than if 2P+1 is also prime, P is known as a Sophie Germaine prime. There are many such primes but only 71  pairs with three to eleven digits if  both primes are palindromic. Above are the lowest and the highest such pairs.

If Q (2P+1) is itself a Sophie Germaine prime there are a total of 19 such triplets where each prime is palindromic. They range in size from 23 digits long to 39 digits long The smallest such triplet follows:

19091918181818181919091,     38183836363636363838183,      76367672727272727676367

Harvey Dubner, JRM 26:1, 1994, pp38-41t

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Palindromic Sophie Germaine Primes (2)

If we let A=1, B=2, C=3, etc than

P+A+L+I+N+D+R+O+M+E+S + A+R+E + F+U+N = 191

Also

15551 (the smallest palindromic prime producing another in this way) when written in words

F+I+F+T+E+E+N + T+H+O+U+S+A+N+D +
F+I+V+E + H+U+N+D+R+E+D + F+I+F+T+Y + O+N+E =
383


This courtesy of G. L. Honaker, Jr. (See Prime Queen Problem below)

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Prime 30103

30103 is the only known multi-digit palindromic prime found by averaging the divisors of a composite number.

30103 = (1 + 5 + 173 + 865 + 29929 + 149645)/6
30103 = (1 + 2 + 3 + 6 + 173 + 346 + 519 + 1038 + 29929 + 59858 + 89787 + 179574)/12

30103 = average of divisors of 149645
30103 = average of divisors of 179574

It was found by Jud McCranie and G. L. Honaker, Jr. in July/98.

See Carlos Rivera’s Prime Puzzles & Problems

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Fermat & Mersenne Numbers

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Fermat numbers , when expressed in binary, have all zeros with a one at each end. Mersenne numbers have all ones.
Both the decimal and binary numbers are palindromes (read the same backwards as forewards).

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Minimum Difference Prime Squares

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These two squares each contain the 25 primes that are less then 100.

Add
The maximum sum of any row, column or diagonal is 213
The minimum sum is 211
The difference (which is the minimum possible) is 2

Multiply
The maximum product of any line, column or diagonal is 19013871
The minimum product is 18489527
The difference which is also the minimum possible .is 524344

JRM vol. 26: 4, 1994 ,p. 308,309 Prob. 2094 proposed by R. M. Kurchan, solution by M. Reed

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Prime Queen Problem

Proposed by G. L. Honaker, Jr. on Nov. 15, 1998.

37

24

45

4

39

22

47

62

44

5

38

23

46

61

40

21

25

36

43

60

3

20

63

48

6

59

26

35

64

41

2

19

27

30

57

42

1

34

49

12

58

7

54

29

52

13

18

15

31

28

9

56

33

16

11

50

8

55

32

53

10

51

14

17

Find the greatest number of prime squares that a queen can attack if placed on an n by n knight's tour solution. For the purpose of this problem, when considering if the queen is attacking a particular square, assume the intervening squares are vacant.
The knight's tour is a numbered tour of a knight over a otherwise empty board visiting each square once only.
The possible tour solutions are in the trillions.

3

14

19

24

1

20

9

2

13

18

15

4

25

8

23

10

21

6

17

12

5

16

11

22

7

By early December, 1998, Mike Keith had found these two solutions.. The order-8 has all of the 18 prime numbers less then 64 under attack by the queen placed on number 35. The order-5 square is also perfect because the queen is attacking all 9 of the primes when placed on the number 25.

In fact, Mr. Keith found perfect solutions also for order-6 and order-7 squares. It is impossible to have a knight tour solution for orders 2, 3 , or 4 and Mr. Keith conjectures that it is impossible to have a perfect solution for boards of order-9 or greater.

Can you find any other perfect solutions to this problem?

Addendum:

On April 1, 2004, I received an email from Jacques Tramu. He enclosed a solution he had found for the perfect order 9 square of this type. All 22 primes in the number range of 1 to 81 are attacked by the queen.

He shows  the solution at http://mapage.noos.fr/echolalie/q9.htm

A few days later I also received a notice of this solution from G. L. Honaker, Jr.,  the originator of this problem.

13 76 15 20 11 74 25 22 9
16 19 12 75 26 21 10 67 24
77 14 17 28 73 56 23 8 69
18 81 78 43 60 27 68 57 66
79 44 29 2 55 72 59 70 7
30 51 80 61 42 3 36 65 58
45 48 41 52 1 54 71 6 35
50 31 46 39 62 33 4 37 64
47 40 49 32 53 38 63 34 5

Addendum2:
April 12, 2004. 5 minutes after uploading the previous addendum, I checked my email. Another update from G.L.
Jacques has just published a perfect order 10! See it at his link shown above.

See Mike Keith's information on this problem at http://users.aol.com/s6sj7gt/primeq.htm

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Ulam's Prime Spiral

272

213

214

215

216

217

218

219

220

221

222

223

224

225

226

227

271

212

161

162

163

164

165

166

167

168

169

170

171

172

173

228

270

211

160

117

118

119

120

121

122

123

124

125

126

127

174

229

269

210

159

116

81

82

83

84

85

86

87

88

89

128

175

230

268

209

158

115

80

53

54

55

56

57

58

59

90

129

176

231

267

208

157

114

79

52

33

34

35

36

37

60

91

130

177

232

266

207

156

113

78

51

32

21

22

23

38

61

92

131

178

233

265

206

155

112

77

50

31

20

17

24

39

62

93

132

179

234

264

205

154

111

76

49

30

19

18

25

40

63

94

133

180

235

263

204

153

110

75

48

29

28

27

26

41

64

95

134

181

236

262

203

152

109

74

47

46

45

44

43

42

65

96

135

182

237

261

202

151

108

73

72

71

70

69

68

67

66

97

136

183

238

260

201

150

107

106

105

104

103

102

101

100

99

98

137

184

239

259

200

149

148

147

146

145

144

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139

138

185

240

258

199

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241

257

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